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Monday, December 12, 2016

Underlying set of affine schemes


Examples: (using division algorithm we can find points of the first three schemes)
  • \text{Spec} \mathbb{C}[x]: closed points and generic pt;
  • \mathbb{A}^1_k for algebraically closed k: same;
  • \mathbb{A}^1_k for any k has infinitely many point (imitate Euclid's proof of infinitude of primes). 
  • \text{Spec}\mathbb{Z};
  • \text{Spec} k;
  • \text{Spec}k[\epsilon]/(\epsilon^2) where k[\epsilon]/(\epsilon^2) is called the ring of dual numbers;
  • \mathbb{A}^1_{\mathbb{R}}= \text{Spec} \mathbb{R}[x] = \{(0), (x-a), (x^2 + ax + b) \mid \text{irreducible}\} (use the fact that \mathbb{R}[x] is a UFD.)
    Note that the (x-a) are maximal ideals (x^2 + ax + b) as the corresponding quotients are always fields. In particulat, \mathbb{R}[x]/(x^2 + ax + b) \cong \mathbb{C}.
    So $\mathbb{A}^1_{\mathbb{R}} is the complex plane folded along real axis, where Galois-conjugate points are glued. 
  • \mathbb{A}^1_{\mathbb{Q}}
  • Closed points of \mathbb{A}^n_{\mathbb{Q}} are just Galois-conjugate glued together
  • \mathbb{A}^1_{\mathbb{F}_p} = \{(0), (f(x))\mid \text{ irreducible }\} (use the fact that \mathbb{F}_p[x] is a Euclidean domain)
    Think of f \leftrightarrow roots of f (i.e. set of Galois conjugates in \overline{\mathbb{F}_p}.
    \mathbb{A}^1_{\mathbb{F}_p} is bigger than \mathbb{F}_p. A polynomial f(x) is not determined by its value at \mathbb{F}_p (e.g. x^p - x), but it is uniquely determined by its valued on \mathbb{A}^1_{\mathbb{F}_p} (as it is a reduced scheme). 
  • \mathbb{A}^2_{\mathbb{C}} = \text{Spec} \mathbb{C}[x,y] = \{(0), (x-a, y-b), f(x,y) \mid f \text{ irreducible}\}.
  •  \mathbb{A}^n_{\mathbb{C}} 

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